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Refer to the exhibit. A network engineer must configure router R1 with a host route to the server. Which command must the engineer configure?
Answer: A
The first address must be the destination. To reach host 10.10.10.10 you send the traffic to the next hop (Router 2 in this case) 192.168.0.2
Source: Adapted from community discussion — [Removed]
Refer to the exhibit. IPv6 is being implemented within the enterprise. The command ipv6 unicast-routing is configured. Interface Gig0/0 on R1 must be configured to provide a dynamic assignment using the assigned IPv6 block. Which command accomplishes this task?
Answer: C
Option ‘c’ is almost correct. Option ‘a’ is incorrect. It assigns a static LLA to the interface (128 bits defined). Option ‘b’ is incorrect. This assigns a static GUA to the interface (128 bits defined). Option ‘c’ is incorrect. It is attempting to assign an IPv6 address, and add eui-64 to the end Option ‘d’ is incorrect. There are no options to the command ipv6 address autoconfig. However, imagine option ‘c’ had a typo; it is missing a ‘/’ before the 64. Now, it would read: ipv6 address 2001:DB8:FFFF:FCF3::/64 eui-64 Then, option ‘c’ is correct.
Source: Adapted from community discussion — PaddyInNZ
Refer to the exhibit. With which metric does router R1 learn the route to host 172.16.0.202?
Answer: C
Refer to the exhibit. A network engineer must configure the link with these requirements: • Consume as few IP addresses as possible. • Leave at least two additional useable IP addresses for future growth. Which set of configurations must be applied?
Answer: C
As per the exhibit, there's a requirement to configure the link and also keep 2 spare IP addresses for future use. So, calculate like this: 2 IPs for Network ID and broadcast IP for whatever subnet we use. 2 IPs for connected interfaces on each router i.e. 1 for R1 gi0/0/0 and 1 for R2 gi0/0/0. 2 IPs reserved for future use. In this way, we need atleast 6 IPs here and the subnet that can provide a closest value in terms of total required IPs is /29 (255.255.255.248). The /29 subnet provides a total of 8 IPs addresses per subnet and out of that 6 are host usable IPs. So, for given subnet 10.10.10.X/29 we can have IP range from 10.10.10.0 - 10.10.10.7. Where 10.10.10.0 will be network ID and 10.10.10.7 will be broadcast IP. Rest 10.10.10.1 - 10.10.10.6 can be used to assign to any hosts of links.
Source: Adapted from community discussion — Vikramaditya_J
DRAG DROP - Drag and drop the device behaviors from the left onto the matching HSRP state on the right.
This is an interactive task on the real exam — a drag-and-drop, hotspot or ordering question. There is nothing to select here, so the answer is shown below for reference.
Answer: See figure below
from top to bottom:: Is forwarding packets has heard from neighbor device, receiving hello packets is waiting to hear from neighbor device is transmiting and receiving hello packets is ready to forward packets if active device fail pls correct me if I m not right
Source: Adapted from community discussion — gewe
Refer to the exhibit. A static route must be configured on R86 to forward traffic for the 172.16.34.0/29 network, which resides on R14. Which command must be used to fulfill the request?
Answer: B
Refer to the exhibit. An engineer must configure a floating static route on an external EIGRP network. The destination subnet is the /29 on the LAN interface of R86. Which command must be executed on R14?
Answer: C
External EIGRP has an AD of 170 unlike Regular EIGRP that has an AD of 90. So by putting 171 makes it a floating static route.
Source: Adapted from community discussion — SVN05
Refer to the exhibit. What is the next-hop IP address for R2 so that PC2 reaches the application server via EIGRP?
Answer: B
DRAG DROP -
This is an interactive task on the real exam — a drag-and-drop, hotspot or ordering question. There is nothing to select here, so the answer is shown below for reference.
Answer: See figure below
R1 - ip route 10.10.13.0 255.255.255.128 10.10.10.1 R2 - ip route 10.10.13.0 255.255.255.128 10.10.10.5 R2 - ip route 10.10.14.0 255.255.255.0 10.10.10.2 R3- ip route 10.10.14.0 255.255.255.0 10.10.10.6
Source: Adapted from community discussion — Simon_1103
Which two network actions occur within the data plane? (Choose two.)
Answer: CD
– De-encapsulating and re-encapsulating a packet in a data-link frame (routers, Layer 3 switches) – Adding or removing an 802.1Q trunking header (routers and switches) – Matching an Ethernet frame’s destination Media Access Control (MAC) address to the MAC address table (Layer 2 switches) – Matching an IP packet’s destination IP address to the IP routing table (routers, Layer 3 switches) – Encrypting the data and adding a new IP header (for virtual private network [VPN] processing) – Changing the source or destination IP address (for Network Address Translation [NAT] processing) – Discarding a message due to a filter (access control lists [ACLs], port security
Source: Adapted from community discussion — Anas_Ahmad
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